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The Python code will be generated here: 

About Python Programming Language

Python is a versatile, general purpose, beginner-friendly programming language that emphasizes on readability and simplicity. Python can be used on a server to create web applications. Python supports procedural, object oriented and functional programming. It is often referred to as a "batteries included" language due to its comprehensive standard library. In recent years, Python has gained popularily in terms of Data science and Machine Learning.

How to use our Python code generator?

This free tool helps you generate Python code based on your instructions with just a single click of a button. To use our tool, follow these steps:-
    1. Enter your prompt, for example, "Generate Fibonacci sequence in Python".
    2. Click on "Generate."
    3. You will see the resulting Python code in the output box.

Examples of some Python code generated by our AI tool

Below are some examples generated by our Python code generator. Please note that you might not receive the same code, as it is generated by an AI model that provides different answers every time and updates periodically.
User Prompt:
Calculate the area of a circle using Python.
from math import pi

def circle_area(radius):
    return pi * radius ** 2

radius = 3
print("Area of the circle with radius", radius, "is", circle_area(radius))
User Prompt:
Find the Longest Common Subsequence (LCS) of Two Strings
def lcs(str1, str2):
    m = len(str1)
    n = len(str2)
    dp = [["" for _ in range(n + 1)] for _ in range(m + 1)]
    for i in range(1, m + 1):
        for j in range(1, n + 1):
            if str1[i - 1] == str2[j - 1]:
                dp[i][j] = dp[i - 1][j - 1] + str1[i - 1]
                dp[i][j] = max(dp[i - 1][j], dp[i][j - 1], key=len)
    return dp[m][n]

str1 = "ABCBDAB"
str2 = "BDCAB"
print("Longest common subsequence:", lcs(str1, str2))
User Prompt:
Check for Balanced Parentheses in an Expression
def is_balanced(expression):
    stack = []
    opening_brackets = "([{"
    closing_brackets = ")]}"
    for char in expression:
        if char in opening_brackets:
        elif char in closing_brackets:
            if not stack or opening_brackets.index(stack.pop()) != closing_brackets.index(char):
                return False
    return not stack

expr = "{[()()]}"
if is_balanced(expr):
    print(expr, "is balanced")
    print(expr, "is not balanced")
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